- 积分
- 47559
- 贡献
-
- 精华
- 在线时间
- 小时
- 注册时间
- 2012-11-14
- 最后登录
- 1970-1-1
|
发表于 2016-9-19 23:45:08
|
显示全部楼层
简单写了下,你可以试试
- !结果为rmark(1:n)其中1,2,3分别表示三类连续降水
- m1 = m2 = 0
- if (rain(1) >= 0.1) then
- m = 1
- end if
- do i = 1 , n
- if (rain(i) >= 0.1) then
- m1 = m1 + 1 ; m2 = m2 + 1
- else if (rain(i) < 0.1 .and. rain(i-1) >= 0.1) then
- m1 = m1 + 1 ; m2 = m2
- else if (rain(i) < 0.1 .and. rain(i-1) < 0.1) then
- m1 = m1 - 1
- if (m1 >= 5 .and. m1 < 7 .and. m2 == m1) then
- rmark(i-m1-1 : i-2) = 1
- else if (m1 >= 7 .and. m1 < 10 .and. m1-m2 <= 1) then
- rmark(i-m1-1 : i-2) = 2
- else if (m1 >= 11 .and. m1-m2 <= 2) then
- rmark(i-m1-1 : i-2) = 3
- end if
- m1 = 0 ; m2 = 0
- end if
- if (i == n) then
- if (m1 >= 5 .and. m1 < 7 .and. m2 == m1) then
- rmark(n-m1-1 : n) = 1
- else if (m1 >= 7 .and. m1 < 10 .and. m1-m2 <= 1) then
- rmark(n-m1-1 : n) = 2
- else if (m1 >= 11 .and. m1-m2 <= 2) then
- rmark(n-m1-1 : n) = 3
- end if
- end if
- end do
复制代码
|
|