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本帖最后由 陌上花开123456 于 2014-5-26 16:14 编辑
我输出多元回归系数以便后面计算,但是运行不出结果,把格点总数XY(220*120)改小一点可以运行,程序的结果如图片所示,以下为我的程序代码,红色标记为问题所在,蓝色部分为子程序,请问该怎么解决?
program main
parameter (N=324)
parameter (k=3)
c ******* K predictor variables
parameter (MM=4)
integer,parameter::xy=220*120
c******** Note that MM=K+1 *****************
dimension y(N),x(k,N),a(MM),b(mm,mm),v(k)
c double precision x,y,a,b,v,q,s,r,u
dimension ob(n,xy),x1(n,xy),x2(n,xy),x3(n,xy)
open(11,file='H:\2013\DATA\duoyuan\CSFR-pr.dat',form='binary')
read(11)((ob(it,ii),it=1,n),ii=1,xy)
open(22,file='H:\2013\DATA\duoyuan\bcc-csm1-1-m-pr.dat',
&form='binary')
read(22)((x1(it,ii),it=1,n),ii=1,xy)
open(33,file='H:\2013\DATA\duoyuan\CNRM-CM5-pr.dat',form='binary')
read(33)((x2(it,ii),it=1,n),ii=1,xy)
open(44,file='H:\2013\DATA\duoyuan\CCSM4-pr.dat',form='binary')
read(44)((x3(it,ii),it=1,n),ii=1,xy)
print*,'ok1'
do ii=1,26400
do it=1,n
y(it)=0.0
x(1,it)=0.0
x(2,it)=0.0
x(3,it)=0.0
enddo
do it=1,n
y(it)=ob(it,ii)
x(1,it)=x1(it,ii)
x(2,it)=x2(it,ii)
x(3,it)=x3(it,ii)
enddo
open(1,file='H:\2013\DATA\duoyuan\a\a0.txt',form='formatted')
open(3,file='H:\2013\DATA\duoyuan\a\a.txt',form='formatted')
call isqt2(x,y,k,mm,n,a,q,s,r,v,u,b,dyy)
c write(*,88) a(1)
write(1,88) a(1)
88 format(/1x,'b 0=',f9.5)
do 89 j=2,mm
c write(*,100) j-1,a(j)
89 write(3,100) j-1,a(j)
100 format(1x,'b',i2,'=',f9.5)
cccccccccccccccccccccccccccccccccccccccccccccccccccccc
c write(*,20)q,s,r
20 format(1x,'q=',f13.6,3x,'s=',f13.6,3x,'r=',f13.6)
c write(*,22)q,u,dyy
22 format(1x,'q=',f13.6,3x,'u=',f13.6,3x,'dyy=',f13.6)
c write(*,30)(i,v(i),i=1,k)
30 format(1x,'v(',i2,')=',f13.6)
c write(*,40)u
40 format(1x,'u=',f13.6)
open(6,file='H:\2013\DATA\duoyuan\a\b.txt')
write(6,180)
180 format(/2x,'regression coefficients:')
write(6,88) a(1)
do 189 j=2,mm
189 write(6,100) j-1,a(j)
write(6,200)
200 format(/1x,'Generic Analysis of Variance Table for the Multiple
* Linear Regression')
write(6,202)
202 format(/1x,'-----------------------------------------------------
*---------------')
write(6,204)
204 format(/3x,'Source df SS MS')
write(6,202)
write(6,206) n-1,dyy
206 format(/1x,'Total n-1=',i2,' SST=',f8.4)
u2=u/real(K)
write(6,208) k,u,u2
208 format(/1x,'Regression K=',i2,' SSR=',f8.4,' MSR=SSR/K='
*,f8.4)
q2=q/real(n-k-1)
write(6,209) n-k-1,q,q2
209 format(/1x,'Residual n-k-1=',i2,' SSE=',f8.4,' MSE=SSE/(n-k-1)
*=',f8.4)
f=(u/real(k))/(q/real(n-k-1))
write(6,220) f
220 format(/1x,' F=MSR/MSE=',f9.4)
write(6,202)
close(6)
end do
stop
end
cccc这是多元线性回归中计算各个参数的子程序,为以上主程序中的调用
subroutine isqt2(x,y,m,mm,n,a,q,s,r,v,u,b,dyy)
dimension x(m,n),y(n),a(mm),b(mm,mm),v(m)
c real x,y,a,b,v,q,s,r,u,yy,dyy,p,pp
c double precision x,y,a,b,v,q,s,r,u,yy,dyy,p,pp
b(1,1)=n
do 20 j=2,mm
b(1,j)=0.0
do 10 i=1,n
10 b(1,j)=b(1,j)+x(j-1,i)
b(j,1)=b(1,j)
20 continue
do 50 i=2,mm
do 40 j=i,mm
b(i,j)=0.0
do 30 k=1,n
30 b(i,j)=b(i,j)+x(i-1,k)*x(j-1,k)
b(j,i)=b(i,j)
40 continue
50 continue
a(1)=0.0
do 60 i=1,n
60 a(1)=a(1)+y(i)
do 80 i=2,mm
a(i)=0.0
do 70 j=1,n
70 a(I)=a(i)+x(i-1,j)*y(j)
80 continue
call achol(b,mm,1,a,l)
yy=0.0
do 90 i=1,n
90 yy=yy+y(i)/n
q=0.0
dyy=0.0
u=0.0
cccccccccccccccccccccccccccccccccc
do 110 i=1,n
p=a(1)
do 100 j=1,m
100 p=p+a(j+1)*x(j,i)
q=q+(y(i)-p)*(y(i)-p)
dyy=dyy+(y(i)-yy)*(y(i)-yy)
u=u+(yy-p)*(yy-p)
110 continue
cccccccccccccccccccccccccccccccccc
s=sqrt(q/n)
r=sqrt(1.0-q/dyy)
do 150 j=1,m
p=0.0
do 140 i=1,n
pp=a(1)
do 130 k=1,m
if(k.ne.j)pp=pp+a(k+1)*x(k,i)
130 continue
p=p+(y(i)-pp)*(y(i)-pp)
140 continue
v(j)=sqrt(1.0-q/p)
150 continue
return
end
subroutine achol(a,n,m,d,l)
dimension a(n,n),d(n,m)
c real a,d
c double precision a,d
l=1
if(a(1,1)+1.0.eq.1.0)then
l=0
write(*,30)
return
endif
a(1,1)=sqrt(a(1,1))
do 10 j=2,n
10 a(1,j)=a(1,j)/a(1,1)
do 100 i=2,n
do 20 j=2,i
20 a(i,i)=a(i,i)-a(j-1,i)*a(j-1,i)
if(a(i,i)+1.0.eq.1.0)then
l=0
write(*,30)
return
endif
30 format(1x,'fail')
a(i,i)=sqrt(a(i,i))
if(i.ne.n)then
do 50 j=I+1,n
do 40 k=2,i
40 a(i,j)=a(i,j)-a(k-1,i)*a(k-1,j)
50 a(i,j)=a(i,j)/a(I,i)
endif
100 continue
do 130 j=1,m
d(1,j)=d(1,j)/a(1,1)
do 120 i=2,n
do 110 k=2,i
110 d(i,j)=d(i,j)-a(k-1,i)*d(k-1,j)
d(i,j)=d(i,j)/a(i,i)
120 continue
130 continue
do 160 j=1,m
d(n,j)=d(n,j)/a(n,n)
do 150 k=n,2,-1
do 140 i=k,n
140 d(k-1,j)=d(k-1,j)-a(k-1,i)*d(i,j)
d(k-1,j)=d(k-1,j)/a(k-1,k-1)
150 continue
160 continue
return
end
32
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