使用dir命令以后为何只出现一个文件名

温骸

文件夹中一共有91 个mat文件
clear;clc;close all
cd('H:\HYCOM\GLBa0.08Indian\1992\data')
filename=dir('*.mat');
dataname=filename.name;
如此处理以后为何只读取了一个文件的名字

温骸

不对，是为何全都保存在一个格子里了，需要怎样做才能把他们分开来

温骸

使用dataname=[filename.name];之后工作空间里的输出
data19921002.matdata19921003.matdata19921004.matdata19921005.matdata19921006.matdata19921007.matdata19921008.matdata19921009.matdata19921010.matdata19921011.matdata19921012.matdata19921013.matdata19921014.matdata19921015.matdata19921016.matdata19921017.matdata19921018.matdata19921019.matdata19921020.matdata19921021.matdata19921022.matdata19921023.matdata19921024.matdata19921025.matdata19921026.matdata19921027.matdata19921028.matdata19921029.matdata19921030.matdata19921031.matdata19921101.matdata19921102.matdata19921103.matdata19921104.matdata19921105.matdata19921106.matdata19921107.matdata19921108.matdata19921109.matdata19921110.matdata19921111.matdata19921112.matdata19921113.matdata19921114.matdata19921115.matdata19921116.matdata19921117.matdata19921118.matdata19921119.matdata19921120.matdata19921121.matdata19921122.matdata19921123.matdata19921124.matdata19921125.matdata19921126.matdata19921127.matdata19921128.matdata19921129.matdata19921130.matdata19921201.matdata19921202.matdata19921203.matdata19921204.matdata19921205.matdata19921206.matdata19921207.matdata19921208.matdata19921209.matdata19921210.matdata19921211.matdata19921212.matdata19921213.matdata19921214.matdata19921215.matdata19921216.matdata19921217.matdata19921218.matdata19921219.matdata19921220.matdata19921221.matdata19921222.matdata19921223.matdata19921224.matdata19921225.matdata19921226.matdata19921227.matdata19921228.matdata19921229.matdata19921230.matdata19921231.mat   成了这样一行，求助。。。

温骸

自己解决了 写成这样就可以了

温骸

dataname={filename.name}';