用Fortran做eof原始和据平贡献差不多，哪里错了？

weijiade99 · 发表于 2019-8-10 10:19:11

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C THIS IS A PROGRAM FOR CACULATING EMPIRICAL ORTHOGONAL FUNCTION
PROGRAM EOF
PARAMETER(N=50,M=160,JOB=1)
DIMENSION F(N,M),T(N,M),IX(M),V(M,M),A(M,M),
   & D(M),W(M),H(N,M),B(M),Z(M),H1(M),V1(M,M),FM(M)
C ***********************************************
C * N: SAMPLE SIZE                         *
C * M: NUMBER OF STATION OR GRID POINT       *
C * JOB: CONTRAL PARAMETER;                   *
C    *    WHEN JOB=0 ORIGINAL DATA;             *
C *    WHEN JOB=1 DEPATURE DATA;             *
C *    WHEN JOB=2 STANDARDIZE DATA.          *
C * F(N,M): ORIGINAL DATA FIELD                *
C * D(M): EIGENVALUE                         *
C * V(M,M): CHARACTERISTIC VECTOR             *
C * T(N,M): TIME COE FFICIENT                *
C ***********************************************
OPEN(11,FILE='F:\zhang3\qw.txt')
READ(11,*)((F(I,J),J=1,M),I=1,N)
OPEN(6,FILE='F:\zhang3\14.txt',STATUS='NEW')
*************************
   open(7,FILE='F:\zhang3\er.grd',form='binary')
open(8,FILE='F:\zhang3\et.grd',form='binary')
*****************************
CALL SEOF(M,N,JOB,F,H,T,IX,V,A,D,W,FM,B,Z,H1,V1)
STOP
END
SUBROUTINE SEOF(N,LL,JOB,F,H,T,IX,V,A,D,W,FM,B,Z,H1,V1)
DIMENSION F(LL,N),T(LL,N),IX(N),V(N,N),A(N,N),D(N),
   & W(N),H(LL,N),B(N),Z(N),H1(N),V1(N,N),FM(N)
IF(JOB.EQ.0)THEN
GOTO 1
ELSE IF(JOB.EQ.1)THEN
GOTO 2
ELSE
GOTO 3
END IF
  1 DO 10 I=1,LL
DO 10 J=1,N
  10 H(I,J)=F(I,J)
GOTO 111
  2 CALL DEP(N,LL,F,H,W)
GOTO 111
  3 CALL NOR(N,LL,F,H,FM,W)
  111 CONTINUE
DO 20 I=1,N
DO 20 J=1,N
A(I,J)=0.0
DO 17 K=1,LL
  17 A(I,J)=A(I,J)+H(K,I)*H(K,J)
A(J,I)=A(I,J)
  20 CONTINUE
WRITE(6,200)
  200 FORMAT(30X,'---------------EOF---------------')
WRITE(6,900)
  900 FORMAT(//20X,'****** CORVARINCE ******')
DO 800 I=1,N
WRITE(6,801)I,(A(I,J),J=1,N)
  801 FORMAT(2X,I3/(2X,8F15.4))
  800 CONTINUE
CALL JACOBI (N,.TRUE.,D,IRT,B,Z,V,A)
DO 400 I=1,N
  400 IX(I)=I
DO 401 I=1,N-1
DO 402 J=I+1,N
IF(ABS(D(I)).GE.ABS(D(J))) GOTO 402
W1=D(I)
D(I)=D(J)
D(J)=W1
K=IX(I)
IX(I)=IX(J)
IX(J)=K
  402 CONTINUE
  401 CONTINUE
WRITE (6,104)
  104 FORMAT (//20X,'******* EIGENVALUE VALUE ******')
WRITE(6,500)(IX(I),I=1,N)
  500 FORMAT(/20X,'MAX-MIN'/(12X,20I5))
WRITE(6,501)(D(I),I=1,N)
  501 FORMAT(2X,8F15.5)
DO 502 J=1,N
ILW=IX(J)
DO 503 I=1,N
  503 V1(I,J)=V(I,ILW)
  502 CONTINUE
WRITE (6,105)
  105 FORMAT (//20X, '****** CHARACTERISTIC VECTOR ******')
DO 600 I=1,N
WRITE(6,601)(V1(I,J),J=1,10)
*************************************
write(7) (V1(i,j),j=1,2)
***********************************
  601 FORMAT(10X,10F10.2)
  600 CONTINUE
DO 25 L=1,LL
DO 25 J=1,N
T(L,J)=0.
DO 31 I=1,N
  31 T(L,J)=T(L,J)+F(L,I)*V1(I,J)
  25 CONTINUE
WRITE (6,106)
  106 FORMAT (///20X, '****** TIME COEFFICIENT ******')
DO 700 I=1,LL
WRITE(6,701)(T(I,J),J=1,10)
*****************************
write(8)(T(I,J),J=1,2)
*****************************************
  701 FORMAT(10X,10F10.2)
  700 CONTINUE
DO 705 I=1,LL
  705 CONTINUE
AP=0.0
DO 702 I=1,N
  702 AP=AP+D(I)
DO 703 I=1,N
AP1=0.0
DO 704 J=1,I
  704 AP1=AP1+D(J)
  703 H1(I)=1.0*AP1/AP
WRITE(6,107)
  107 FORMAT(//20X,'****** ACCUMULATE PROPORTION ****** ')
WRITE(6,108)(H1(I),I=1,N)
  108 FORMAT(/10X,10F10.5)
RETURN
END
SUBROUTINE DEP(N,LL,F,H,W)
DIMENSION F(LL,N),H(LL,N),W(N)
DO 10 J=1,N
W(J)=0.0
DO 20 I=1,LL
  20 W(J)=W(J)+F(I,J)
W(J)=W(J)/FLOAT(LL)
  10 CONTINUE
DO 30 J=1,N
DO 30 I=1,LL
H(I,J)=F(I,J)-W(J)
  30 CONTINUE
RETURN
END
SUBROUTINE NOR(N,LL,F,H,FM,W)
DIMENSION F(LL,N),H(LL,N),FM(N),W(N)
DO 10 J=1,N
W(J)=0.0
DO 20 I=1,LL
  20 W(J)=W(J)+F(I,J)
FM(J)=W(J)/FLOAT(LL)
W(J)=0.0
DO 30 I=1,LL
  30 W(J)=W(J)+(F(I,J)-FM(J))**2
W(J)=SQRT(W(J)/FLOAT(LL))
DO 40 I=1,LL
  40 H(I,J)=(F(I,J)-FM(J))/W(J)
  10 CONTINUE
RETURN
END
SUBROUTINE JACOBI(N,EV,D,IRT,B,Z,V,A)
DIMENSION D(N),B(N),Z(N),V(N,N),A(N,N)
LOGICAL EV
IF(. NOT. EV) GOTO 20
DO 10 K=1,N
DO 10 L=1,N
IF (K-L) 5,6,5
6 V (K,K)=1.0
GOTO 10
5 V(K,L)=0.0
  10 CONTINUE
  20 DO 30 K=1,N
B(K)=A(K,K)
D(K)=B(K)
  30 Z(K)=0.0
IRT=0
DO 200 I=1,50
SM=0.0
N1=N-1
DO 40 K=1,N1
K1=K+1
DO 40 L=K1,N
  40 SM=SM+ABS(A(K,L))
IF (SM)101,210,101
  101 IF(I-4)50,60,60
  50 TRESH=0.2*SM/(FLOAT(N)*FLOAT(N))
GOTO 70
  60 TRESH=0.0
  70 DO 180 K=1,N1
K1=K+1
DO 180 L=K1,N
G=100.0*ABS(A(K,L))
IF (I. GT. 4. AND. ABS(D(K))+G. EQ. ABS(D(K)).
   *  AND. ABS(D(L))+G.EQ. ABS(D(L))) GOTO 170
IF (ABS(A(K,L)). LE . TRESH) GOTO 180
H=D(L)-D(K)
IF (ABS(H)+G.EQ.ABS(H)) GOTO 80
THETA=0.5*H/A(K,L)
T=1.0/(ABS(THETA)+SQRT(1.0+THETA*THETA))
IF (THETA. LT. 0.0) T=-T
GOTO 90
  80 T=A(K,L)/H
  90 C=1.0/SQRT(1.0+T*T)
S=T*C
H=T*A(K,L)
Z(K)=Z(K)-H
Z(L)=Z(L)+H
D(K)=D(K)-H
D(L)=D(L)+H
A(K,L)=0.0
KM1=K-1
IF (KM1) 120,120,100
100 DO 110 J=1,KM1
G=A(J,K)
H=A(J,L)
A(J,K)=C*G-S*H
110 A(J,L)=S*G+C*H
120 L1=L-1
IF (L1-K1)140,300,300
300 DO 130 J=K1,L1
G=A(K,J)
H=A(J,L)
A(K,J)=C*G-S*H
130 A(J,L)=S*G+C*H
140 L1=L+1
IF (L1. GT. N) GOTO 150
DO 145 J=L1,N
G=A(K,J)
H=A(L,J)
A(K,J)=C*G-S*H
145 A(L,J)=S*G+C*H
150 IF (.NOT. EV) GOTO 160
DO 155 J=1,N
G=V(J,K)
H=V(J,L)
V(J,K)=C*G-S*H
155 V(J,L)=S*G+C*H
160 IRT=IRT+1
GOTO 180
170 A(K,L)=0.0
180 CONTINUE
DO 200 K=1,N
D(K)=B(K)+Z(K)
B(K)=D(K)
200 Z(K)=0.0
210 RETURN
END

weijiade99 · 发表于 2019-8-10 10:28:18

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weijiade99 · 发表于 2019-8-10 10:30:58

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