NCL作图，怎样把具体的年月日转换成365天这样的形式？

方莹红

楼主这里有几十年的逐日最高气温数据，现在想要求一个热浪频次，要求连续三天及以上最高气温超过35℃或者有连续两天最高温度大于35℃（其中有一天温度要大于38℃），现在的问题是这个要求时间连续的问题，楼主想不出来用循环怎么实现，如果可以把那些月日都去掉，全部转化成天，就一年就用365天来计算就好了，求助哪位大佬知道NCL有这样的函数可以转化吗？或者有其他的方法可以实现判断连续三天这种条件吗？

khaled

http://www.ncl.ucar.edu/Document ... n/day_of_year.shtml

Examples
Example 1

doy = day_of_year((/1900,1990,1996/),(/3,3,3/),(/1,1,1/)) ; doy = (/60,60,61/)
Example 2
Same as example 1, but using different calendars, which are only recognized in NCL version 6.1.0.

year  = (/1900,1990,1996/)
month = (/3,3,3/)
day   = (/1,1,1/)

;---No calendar
doy = day_of_year(year,month,day)  ; doy = (/60,60,61/)

year@calendar = "standard"
doy = day_of_year(year,month,day)  ; doy = (/60,60,61/)

year@calendar = "julian"
doy = day_of_year(year,month,day)  ; doy = (/61,60,61/)

year@calendar = "noleap"           ; also "365"
doy = day_of_year(year,month,day)  ; doy = (/61,60,60/)

year@calendar = "allleap"          ; also "366"
doy = day_of_year(year,month,day)  ; doy = (/61,61,61/)

year@calendar = "360"
doy = day_of_year(year,month,day)  ; doy = (/61,61,61/)