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各位大神,这个EOF程序里载荷向量所对应的时间系数是哪个,多谢多谢!
[A,B,C]=xlsread('SST.xls');
xx=A;
[m,b]=size(xx);
x=xx';
for i=1:b
x(i,:)=(x(i,:)-mean(x(i,:)));
end
ss=x;
r=ss*ss'/m;
[v,d]=eig(r);
pc=v'*xx';
D=rot90(d,2);
diagonal=diag(D);
eof=fliplr(v);
pc=flipud(pc);
%检查eof的正交性
ae=eof*eof';
%检查pc的正交性
ap=pc*pc';
%回复到x的距平值
ac=eof*pc;
%以上说明计算数据正确
% 求各模态的方差贡献率%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
sum_d=sum(diagonal); % 总的特征值
e1=(diagonal(1,1)/sum_d)*100%; %90.2268%
e2=(diagonal(2,1)/sum_d)*100%; %6.0384%
e3=(diagonal(3,1)/sum_d)*100%; %2.1832%
e4=(diagonal(4,1)/sum_d)*100%; %0.4853%
e5=(diagonal(5,1)/sum_d)*100%; %0.3441%
e6=(diagonal(6,1)/sum_d)*100%;
e7=(diagonal(7,1)/sum_d)*100%;
e8=(diagonal(8,1)/sum_d)*100%;
e9=(diagonal(9,1)/sum_d)*100%;
e10=(diagonal(10,1)/sum_d)*100%;
pc1=pc(1,:);pc2=pc(2,:);pc3=pc(3,:);
f1=eof(:,1);
eof1=reshape(f1,23,1);
f2=eof(:,2);
eof2=reshape(f2,23,1);
f3=eof(:,3);
eof3=reshape(f3,23,1);
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